# How do you graph using the intercepts for #5x + 2y = -2#?

##### 1 Answer

Nov 9, 2015

Plot the intercept points and draw a straight line through them

graph{(5x+2y+2)* ((x+2/5)^2+y^2-0.01)*(x^2+(y+1)^2-0.01)=0 [-4.93, 4.934, -2.465, 2.465]}

#### Explanation:

The x and y intercepts give us two points on the line defined by the linear equation.

The x-intercept is the value of

Given

when

which gives the point

Similarly for the y-intercept

we get the point